50 lines
1.4 KiB
JavaScript
50 lines
1.4 KiB
JavaScript
const express = require("express")
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const app = express()
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const PORT = 3000
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const path = require('path')
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const fs = require('fs')
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const formidable = require('formidable')
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app.get("/", function (req, res) {
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res.sendFile(path.join(__dirname, '/static/form5.html'))
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})
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app.post('/process_upload', function (req, res) {
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let formularz = formidable({
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keepExtensions: true
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})
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formularz.uploadDir = __dirname + '/static/upload/'
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formularz.parse(req, function (err, fields, files) {
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// https://stackoverflow.com/questions/423376/how-to-get-the-file-name-from-a-full-path-using-javascript
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let name_from_path = files.wyslany_plik.path.replace(/^.*[\\/]/, '')
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if (files.wyslany_plik.type == 'text/plain') {
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fs.readFile(files.wyslany_plik.path, function (err, data) {
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let danepliku = {
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"type": files.wyslany_plik.type,
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"path": name_from_path,
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"text": data.toString()
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}
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res.send(JSON.stringify(danepliku))
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})
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} else {
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let danepliku = {
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"type": files.wyslany_plik.type,
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"path": name_from_path,
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"text": ""
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}
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res.send(JSON.stringify(danepliku))
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}
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})
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})
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app.use(express.static('static'))
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app.listen(PORT, function () {
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console.log("start serwera na porcie " + PORT)
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})
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